0=x^2+12x+14

Solution for 0=x^2+12x+14 equation:

0=x^2+12x+14

We move all terms to the left:

0-(x^2+12x+14)=0

We add all the numbers together, and all the variables

-(x^2+12x+14)=0

We get rid of parentheses

-x^2-12x-14=0

We add all the numbers together, and all the variables

-1x^2-12x-14=0

a = -1; b = -12; c = -14;
Δ = b2-4ac
Δ = -122-4·(-1)·(-14)
Δ = 88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{88}=\sqrt{4*22}=\sqrt{4}*\sqrt{22}=2\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{22}}{2*-1}=\frac{12-2\sqrt{22}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{22}}{2*-1}=\frac{12+2\sqrt{22}}{-2}
$